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3w^2-w-3=0
We add all the numbers together, and all the variables
3w^2-1w-3=0
a = 3; b = -1; c = -3;
Δ = b2-4ac
Δ = -12-4·3·(-3)
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{37}}{2*3}=\frac{1-\sqrt{37}}{6} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{37}}{2*3}=\frac{1+\sqrt{37}}{6} $
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